What is the take-off distance required for a boeing 707 at maximum weight?
Answers:
If you don't mind me using an E-3 (modified 707) as an example then I can give you an answer. Lets use Standard day; 15 deg C, Sea Level, Dry Runway and Pratt & Whittney TF-33 engines, a MTOW of 325,000lbs (max taxi wieght) and no controlling obstacle. IF you had an unlimited length of runway with no slope. Here is the EXACT answer:
6589.98 feet.
Well that is exactly what my Takeoff and Landing Data Program told me.
1000m
10 miles
Depends on temperature, humidity, prevailing winds and pressure altitude.
At 130C temp and 100% humidity, with a 90 degree crosswind and the runway at an altitude of 10,000 feet, there is not a runway in the world long enough at MTOW.
I found this "The takeoff field length on a standard day is a relatively long 10 000 feet, which can be directly related to the low thrust loading of 0.23 and the high wing loading of 111.6 pounds per square foot. (See chapter 3 of ref. 176.) " on the following page: http://www.hq.nasa.gov/pao/history/sp-46. . I hope this is helpful.
2.4kh/m
At maximum weight for lift off of a B 707 actually depends on the conditions in which it is lifting off from. Ambient Temperature, Pressure, density Altitude, Take off Configuration, Wind conditions, etc.
At what temp, what altitude and what wind speed??
Average: 10k ft.
Tinkicker, at 130 C, the distance would be zero, because the pilot would be dead and not able to advance the power levers.
Believe Sc0tt; he's got the best answer
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