25 32 37 47 58 71 79 ? Which number is next in this sequence?
Answers:
a(n) = a(n-1) + sum of digits of a(n-1)
25, 32, 37, 47, 58, 71, 79
Next is 79 + 16 = 95.
95
is it....95?!?!?
93 - lucky guess.
25 - 32 i.e 2+5 = 7 So 25+7 = 32
32 - 37 i.e 3+2 = 7 So 32+5 = 32
37 - 47 i.e 3+7 = 10 So 37+10 = 47
So the Answer
79 - ? i.e 7+9 = 16 So 79+16 = 95
Answer - 95
95 see above answer.. can't explain any better than above
95.because 25+7=32.2+5=7
32+5=37.3+2=5
79+16=95.7+9=16
the next number is just the sum of the individual numbers
79,95,109,119,130,134
Integer sequence
right
25+ 7(2+5) = 32
32 + 5(3+2) = 37
37 + 10(3+7) = 47.
79+16(7+9)=95
so 95 is the answer
25 + 2 + 5 = 32
32 + 3 + 2 = 37
37 + 3 + 7 = 47
47 + 4 + 7 = 58
58 + 5 + 8 = 71
71 + 7 + 1 = 79
79 + 7 + 9 = 95
5 million
a1=25,
a(n+1)=a(n)+{sum of digits of a(n)}
a1=25
a2=25+7=32
a3=32+5=37
a4=37+10=47
a5=47+11=58
a6=58+13=71
a7=71+8=79
a8=79+16=95
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a(n+1)=a(n)+{sum of digits of a(n)}
for n=1,2,3......
therefore,the next term is 95
i hope that this helps
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