Plz anyone tell me to find out the oxidation number of PbSO4 , CaOCl2 , (Nh4)2SO4?

OXIDATION NUMBER

Answers:
In PbSO4 the Pb is +2 and the SO4 group is -2.
The O in SO4 is -2 so the sulphur must be +6 (the four oxygens add up to -8 and for the SO4 group to be -2 the sulphur must be +6)
The formula for CaOCl2 IS correct. The Ca is +2 and the OCl2 group -2 as O is usually -2 it would suggest that each chlorine is 0. This anomaly is because the OCl2 is known as a disproportionate ion (having too much chlorine).
In (NH4)2SO4 each NH4 group is +1 and the SO4 is -2.
So as each H = +1 the N is -3. The SO4 has the same oxidation numbers as in PbSO4 above.
In working out oxidation numbers we assume that certain elements have fixed numbers O is -2, Cl is -1, H is +1 and alkali metals like sodium and potassium are +1. The complete compound must add up to zero.
22
A compound doesn't have an oxidation number, but an element in a compound does.
For a simple ion, like Pb in PbSO4, it is the same as the ionic charge, ie +2.
Now, since O is always -2, the S must be +6 to make the whole compound zero.
I don't think that you have written the formula of the calcium compound correctly.
If you use O = -2, S = +6 and H = +1, then you should be able to work out the N in ammonium sulphate.
Pb II, S VI O -II, Ca II, Cl -I (in CaCl) and Cl I (in OCl), N -III, H I

I hope thats what u wanted.

BTW Gervald O can also be -I and -I//II (-1/2)

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