Another maths question?

I have this equation that x = 3 over (x-2)

You are supposed to be able to get 2 answers.

It was very easy to get the first answer to be 3.

I also worked out that x could be equal to -1 but I don't know how I did that! This question probably should be very easy.

Answers:
x = 3/(x-2)

=> x(x-2) = 3
=> x^2 - 2x = 3
=> x^2 - 2x - 3 = 0
=> (x-3) (x+1) = 0

Either x-3 = 0 => x=3
Or x+1 = 0 => x=-1
x = 3 over (x-2)
if x is different from 2 then
x(x-2)=3
x^2 -2x -3 =0
(x+1)(x-3) =0
so x =-1 or x=3
'
x=3/(x-2)
multiplyingby (-2)
x(x-2)=3
x^2-2x-3=0
x^2-3x+x-3=0
x(x-3)+1(x-3)=0
(x+1)(x-3)=0
x=-1 or 3
cross multiply to get x(x-2)=3
so x(squared)-2x-3=0
then (x-3)(x+1)=0
so x=3 or x=-1
cross multiply to get x(x-2)=3
so x(squared)-2x-3=0
then (x-3)(x+1)=0
so x=3 or x=-1
x=3/(x-2)
x(x-2)=3
add 1 to each side
x^2-2x +1=4
(x-1)(x-1)=4
take sqrt of each side,
(x-1) = +2 or -2
>>>>>x= (1+2) or (1-2) = 3 or -1

i hope that this helps
x=3/x-2
cant solve it here but its answer is -1
x = 3/(x-2)
x(x-2) = 3
x^2 -2x -3 = 0
(x +1)(x - 3) = 0
thus x = -1 or x = 3
note: x^2 = x *x = x sqaure
Yes, you were right-either x=3 or x=-1.

In order to do this, you have to try and get all of the x terms on one side, so that you can solve the equation for x.

Thus, multiplying both sides by (x-2), you get:

x(x-2)=3
Expanding, you obtain:
x^2-2x=3
Rearranging yields:
x^2-2x-3=0

Now you need to factorise this:
Note that (x-1)^2=x^2-2x+1.
So, x^2-2x-2=(x-1)^2-4=0
(x-1)^2=4
(x-1)=2 or -2
So, either x=2+1=3, or x=-2+1=-1.

Hope this was helpful!

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