Could you help me to simplify 3pq / 4r to the power of 2 multiplied by 2rs / 6q to the power of 2?

Could you help me to simplify these two equation's
3pq / 4r to the power of 2 multiplied by 2rs / 6q to the power of 2
and
15ab to the power of 2 / 8c to the power of 2 d divided by 3ab / 4cd
If you could set the working out in step's, giving me an explanation at each step

Answers:
(3pq/4r)^2=9p^2q^2/16r^2
(2rs/6q)^2=4r^2s^2/36q^2
(3pq/4r)^2(2rs/6q)^2
=9p^2q^2*4r^2s^2/16r^2*36q^2
=9p^2s^2/4r^2*36q^2
=p^2s^2/16q^2r^2

2.(225a^2b^2/64c^2)/(3ab/4cd)
=225a^2b^2*4cd/64c^2*3ab
=75abd/16c
Try a Bacardi and Coke!
You really need to layout the problem better.
The first equation goes like this:

3pq is simplified to p, as it cancels with the 6q^2.leaving 2q for the 6q^2..the 4r^2 cancels to 2r with the 2rs, which turns to just .s.

thus.you have p/2r multiplied by s over 2q.
this multiplies to get ps/4rq


Im doing the next one..

ok.done:

the next one is:

15ab^2/8c^2 divided by 3ab/4cd

that turns to 15ab^2/8c^2 times by 4cd/3ab

which goes to 5b/2c times by d/1

which equals 5bd/2c.
3pq/10to the power of 2 multiplied by 2rs/6q to the power of 2 is 300pq/400r x 100rs/300q
1-) ps square divided by 16
I didn't understand the second one
1. As both sections are to taken to the power 2 we can perform the simplification first and then raise to the power 2 (ie square it) so we have 3pq/4r times 2rs/6q which simplifies as follows:
3x2 = 6 so the 6 numerator cancells with 6 in the denominator
q numerator cancells with q denominator
r denominator cancells with r numerator
This leaves ps numerator and 4 denominator or ps/4
This is to be squared so the answer is

[p squared x s squared]/16

2. This sum is worded ambiguously eg is it to the power of 2/8c
or is it 15ab to the power of 2 and then divided by 8c
Can't be done
(3pq/4r)^2 x (2rs/6q)^2

= [(9p^2q^2) / (16r^2)] x [(4r^2s^2) / (36q^2)]

=(p^2s^2)/16


[(15ab)^2 / (8c^2)] / [(3ab) / (4cd)]

=[(225a^2b^2) / (64c^2)] * [(4cd) / (3ab)]

=(75abd) / (16c)
(3pq/4r)^2 x (2rs/6q)^2

Expand the squares gives

[(9p^2 q^2 )/ 16 r^2 ] x [4r^2s^2 /36q^2]

Now multiplying the two sides gives

36 p^2 q^2 r^2 s^2 / 576 r^2 q^2

You can divide top and bottom by 36 q^2 r^2 which would give

p^2 s^2 / 16

which can also be expressed as (ps/4)^2

Hope this helps
3pq / 4r to the power of 2 multiplied by 2rs / 6q to the power of 2
= 3pq / (4r)^2 x 2rs / (6q)^2
= 3pq / 16r^2 x 2rs / 36q^2
= (3pq/16r^2) x 2rs / 36q^2
= (3pqs/8r) / 36q^2
= ps/96qr

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