Last one from me for you lot!?
number of occupants -> Number of vehicles
1- 44
2 - 37
3 - 22
4 - 10
5 - 6
6 - 1
more that 6 - 4
avril does some calculations and expects that on tuesday there will be 3520 vehicles with 1 occupant. how many drivers in total does avril expect to pass on tuesday
I JUST NEED TO KNOW HOW TO WORK IT OUT PLEASE IF YOU TELL ME HOW TO WORK IT OUT I CAN DO IT FOR MYSELF :D
Answers:
44 * x = 3520
x = 3520/44
x = 80
80 times total = 80(44+37+22+10+6+1+4)
80 times 124 = 9920 drivers
It's too hard.my brain hurts.
Is this your maths homework?
Its hard to say without atleast some direction, but I would take it this way.
if your first table is relative ratio of number of occupants expected per number of vehicles (44 one passanger vehicles out of 124), then you could figure it out using the following:
44 / 124 = 3520 / n, where n is the total number of cars.
So n = (124 * 3520) / 44
Well 3520 vehicles = 3520 drivers!
(Only one driver can drive per vehicle)
If it's total occupants you want then same technique as above posters, although i'd do it in a table with the following headings:
Occupants Mon
Vehicles Mon
Probability (w1)
Frequency (w2)
Where (w1) is calculated as the monday frequency (eg 44) divided by the total number of vehicles observed (44+37+. etc).
Check through that this adds up to 1 as a check at the bottom of the table.
Where (w2) is the frequency - this is the probability you calculate in w1 x 3520 x no of occupants (mon) vehicles in every case. Add up the total of this column to get the total occupants.
well the first one, all added togetherr, equals 120.
So if on tuesday, there will be 3520 vehicles passing by, divise the 3520by the 120 that's the total of the avarage numbers,
then multiply that answer with the number behind the number of occupants you need in your question and bob's your uncle!
Ok, to start with you need to look at the relative frequencies, so 44 cars out of 120 had one occupant, and we need to know the same proportions when we have 3520 with one occupant.
so 44/124=3520/n where n is the total number of cars.
Rearrange this formula to find n, so (3520x124)/44=n. n=9920. So that is 9920 cars in total that pass on tuesday.
Hope that makes sense!
Work out the total number of vehicles ie 44+37+22+10+6+1+4 and that equals 124. then work out the percentage of vehicles with 1 driver ie 44/124*100 that equals 35.48387%
You then know that 35.48% of the vehicles equals 3520 so then work out 100% of the vehicles ie 3520/35.48387% which is 3520/0.3548387 this equals 9920 which is the answer
answer is.1 vehichle 2 occupants.me and my mate..48 tins of lager..on our way to your house.lets party....!!! now tell me thats the wrong answer.hahahaha..
Well first of all you need to look at the sample day.
You have 124 vehicles that day of which 44 vehicles had only 1 occupant.
You now have to translate this to a day when there are 3520 vehicles with only 1 occupant.
To do this you take do the following sum
3520 / 44 x 124 =
That should give you the answer,
44 vehicles out of 124 carry 1 occupant
therefore, total number of cars passing on tuesday = (3520/44)*124
= 9920 vehicles
assuming that the data taken from the 124- vehicle sample is an accurate representation of of all the vehicles on the road that day
one per vehicle probably
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1- 44
2 - 37
3 - 22
4 - 10
5 - 6
6 - 1
more that 6 - 4
avril does some calculations and expects that on tuesday there will be 3520 vehicles with 1 occupant. how many drivers in total does avril expect to pass on tuesday
I JUST NEED TO KNOW HOW TO WORK IT OUT PLEASE IF YOU TELL ME HOW TO WORK IT OUT I CAN DO IT FOR MYSELF :D
Answers:
44 * x = 3520
x = 3520/44
x = 80
80 times total = 80(44+37+22+10+6+1+4)
80 times 124 = 9920 drivers
It's too hard.my brain hurts.
Is this your maths homework?
Its hard to say without atleast some direction, but I would take it this way.
if your first table is relative ratio of number of occupants expected per number of vehicles (44 one passanger vehicles out of 124), then you could figure it out using the following:
44 / 124 = 3520 / n, where n is the total number of cars.
So n = (124 * 3520) / 44
Well 3520 vehicles = 3520 drivers!
(Only one driver can drive per vehicle)
If it's total occupants you want then same technique as above posters, although i'd do it in a table with the following headings:
Occupants Mon
Vehicles Mon
Probability (w1)
Frequency (w2)
Where (w1) is calculated as the monday frequency (eg 44) divided by the total number of vehicles observed (44+37+. etc).
Check through that this adds up to 1 as a check at the bottom of the table.
Where (w2) is the frequency - this is the probability you calculate in w1 x 3520 x no of occupants (mon) vehicles in every case. Add up the total of this column to get the total occupants.
well the first one, all added togetherr, equals 120.
So if on tuesday, there will be 3520 vehicles passing by, divise the 3520by the 120 that's the total of the avarage numbers,
then multiply that answer with the number behind the number of occupants you need in your question and bob's your uncle!
Ok, to start with you need to look at the relative frequencies, so 44 cars out of 120 had one occupant, and we need to know the same proportions when we have 3520 with one occupant.
so 44/124=3520/n where n is the total number of cars.
Rearrange this formula to find n, so (3520x124)/44=n. n=9920. So that is 9920 cars in total that pass on tuesday.
Hope that makes sense!
Work out the total number of vehicles ie 44+37+22+10+6+1+4 and that equals 124. then work out the percentage of vehicles with 1 driver ie 44/124*100 that equals 35.48387%
You then know that 35.48% of the vehicles equals 3520 so then work out 100% of the vehicles ie 3520/35.48387% which is 3520/0.3548387 this equals 9920 which is the answer
answer is.1 vehichle 2 occupants.me and my mate..48 tins of lager..on our way to your house.lets party....!!! now tell me thats the wrong answer.hahahaha..
Well first of all you need to look at the sample day.
You have 124 vehicles that day of which 44 vehicles had only 1 occupant.
You now have to translate this to a day when there are 3520 vehicles with only 1 occupant.
To do this you take do the following sum
3520 / 44 x 124 =
That should give you the answer,
44 vehicles out of 124 carry 1 occupant
therefore, total number of cars passing on tuesday = (3520/44)*124
= 9920 vehicles
assuming that the data taken from the 124- vehicle sample is an accurate representation of of all the vehicles on the road that day
one per vehicle probably
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