Ethanoic acid can be neutralised by reacting with calcium hydroxide. What products are formed?

Simple, but specific.please!

Answers:
ethanoic acid (CH3COOH) an acid reacts with calcium hydroxide(Ca(OH)2) a base, they will undergo neutralisation to give you salt plus water.
equation:
2CH3COOH(aq) + Ca(OH)2(aq) ---->Ca(CH3COO)2(aq) + 2H2O(l)
hope this helped!
It should be obvious from reading the textbook. Where exactly are you having a problem?
2CH3COOH + Ca(OH)2 ---->Ca(CH3COO)2 + 2H2O

best answer?
two cheeseburgers are formed!
let me guess.

its
1) ethlyoxide?
2) calcium ethlyoxide?
3) caloxide ethane?
Well, Ethanoic acid is vinegar, which is HC2H3O2 and Ca(OH)2

will give you Calcium Acetate plus water

Ca (CH3O2)2 + 2H2O.
Of course the number after the letter is the subscript. Hopes it helps!
In water the acid and bases dissociate to form ions:
Ethanoic acid (acetic acid): CH3-COOH = CH3-COO- H+
Calcium hydroxide: Ca(OH)2 = Ca2+ 2OH-

So you get
Ca2(CH3COO)2 = calcium acetate
plus 2H20 (2 water molecules)
Acid + Base ---> Salt + Water

2CH3COOH + Ca(OH)2 ---> (CH3COO)2Ca + 2H2O
ethanoic acid + calcium hydroxide ---> calcium ethanoate + water

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