How many miles does the earth cover in orbit around the sun?
When I was young I always imagined the earth travelling at nearly 1000mph because it takes 24 hours to cover the equatorial circumference of the earth ( 24000miles).
What is puzzling me is that I am now being told from many astrology and physics websites that the earths orbital speed is actually 29.78km/s (18.5 miles per second or 66620mph).
I need to follow up on this more closely but I suspect the earth's rotation around it's axis must be slower than the speed along it's orbit, well it has got to be!
Does anybody know of any websites that can give me details about this?
I've calculated that the distance covered per year (excluding our own solar system around our galaxy) is, as an estimate 583591200 miles.
Is this right? If not does anybody got a more accurate answer?
Answers:
The surface speed of the Earth's rotation at the equator is 465.11 m/s, while the average orbital speed is 29783 m/s, a good 6 times faster. The orbital circumference would be 2AU*pi, where AU is the astronomical unit, the distance from the Earth to the Sun, or 149597870691 m. So the circumference is 2*149597870691*pi = 939951143084 m, or 584058562 miles, which is very close to your answer; you probably just rounded differently or used a different value for AU.
Hi. It is about 93 million miles to the Sun. This number times Pi is the circumference. Earth travel this circumference in one year. Take the number of hours in a year and divide to find MPH. And please know the difference between astronomy and astrology!
Your number is close to what I have approximated using pi and 93,000,000 miles as the distance to the sun. I have seen the 67,000 mph figure in many texts about the speed of the earth. We are probably rotating around the Milky Way even faster than that and who knows how fast our galaxy is travelling away from the "big bang" origin.
Earth travels at 67000miles /hr around the sun.
It takes 365 days for one orbit, therefore the total mileage is
586920000miles.
Your number is right.
There is no physical connection between the Earth's rotation on its axis and its orbit around the Sun, so I don't understand how you can think that one cannot be faster than then other. After all, the Earth isn't rolling on something. It is just like a baseball in flight between the pitcher and batter. If it is a knuckle ball, it is hardly spinning at all, but if it is a curve ball, it spins very fast. In both cases, the speed of the throw is about the same. The speed of the throw is like the Earth's orbital motion around the sun and the spin of the ball is like the Earth's spin, or daily rotation on its axis.
a bunch
The orbital is an ellipse. However there is there is very little difference between the major[1AU] and minor[.983AU] axes and for all practical purposes we can take the orbit as a circle
with a radius=1AU=93 million miles.
circumference =2*Pi*r
=2*22/7*93*10^6
=584.57 million miles
which is very close to your answer.
Just multiply 64,000 (mph) X 24 X 365 and you will know.
You are right in what you say, however you are confusing two different things. The earth's speed of spin around its axis is approximately 1,000 mph. TThe Earth rotates once in a few minutes under a day (23 hours 56 minutes 04. 09053 seconds). This is called the sidereal period (which means the period relative to stars). The sidereal period is not exactly equal to a day because by the time the Earth has rotated once, it has also moved a little in its orbit around the Sun, so it has to keep rotating for about another 4 minutes before the Sun seems to be back in the same place in the sky that it was in exactly a day before.
An object on the Earth's equator will travel once around the Earth's circumference (40,075.036 kilometers) each sidereal day. So if you divide that distance by the time taken, you will get the speed of rotation (1670 Kph or 1038 mph).
The earth's speed of orbit around the sun is approximately 67,000 mph. It takes roughly 365 days for the Earth to go around the Sun once. This means that the Earth is rushing through space around the Sun at a rate of about 67,000 miles per hour. The circumference of the Earth's orbit is about 940 million kilometers, so if you divide that by the hours in a year (8760) you will get our orbital speed in kilometers per hour (107306 Kph or 66680 mph)
The path of the earth around the sun is an ellipse. But, it's pretty circular. the earth is actually closest to the sun when the northern hemispere has it's winter. Assuming a circle to make it easy to calculate. you only need to use the formula: 2*pi*r this gives you the circumference. the distance from the sun to the earth is 93,000,000 miles which is r. pi is a constant 3.14. Plug into the eaquation and you get an approx anwers. If you need more accuracy you'll have to use an ellipse which has two foci and some memories that I've lost.
sounds about right. well done.
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What is puzzling me is that I am now being told from many astrology and physics websites that the earths orbital speed is actually 29.78km/s (18.5 miles per second or 66620mph).
I need to follow up on this more closely but I suspect the earth's rotation around it's axis must be slower than the speed along it's orbit, well it has got to be!
Does anybody know of any websites that can give me details about this?
I've calculated that the distance covered per year (excluding our own solar system around our galaxy) is, as an estimate 583591200 miles.
Is this right? If not does anybody got a more accurate answer?
Answers:
The surface speed of the Earth's rotation at the equator is 465.11 m/s, while the average orbital speed is 29783 m/s, a good 6 times faster. The orbital circumference would be 2AU*pi, where AU is the astronomical unit, the distance from the Earth to the Sun, or 149597870691 m. So the circumference is 2*149597870691*pi = 939951143084 m, or 584058562 miles, which is very close to your answer; you probably just rounded differently or used a different value for AU.
Hi. It is about 93 million miles to the Sun. This number times Pi is the circumference. Earth travel this circumference in one year. Take the number of hours in a year and divide to find MPH. And please know the difference between astronomy and astrology!
Your number is close to what I have approximated using pi and 93,000,000 miles as the distance to the sun. I have seen the 67,000 mph figure in many texts about the speed of the earth. We are probably rotating around the Milky Way even faster than that and who knows how fast our galaxy is travelling away from the "big bang" origin.
Earth travels at 67000miles /hr around the sun.
It takes 365 days for one orbit, therefore the total mileage is
586920000miles.
Your number is right.
There is no physical connection between the Earth's rotation on its axis and its orbit around the Sun, so I don't understand how you can think that one cannot be faster than then other. After all, the Earth isn't rolling on something. It is just like a baseball in flight between the pitcher and batter. If it is a knuckle ball, it is hardly spinning at all, but if it is a curve ball, it spins very fast. In both cases, the speed of the throw is about the same. The speed of the throw is like the Earth's orbital motion around the sun and the spin of the ball is like the Earth's spin, or daily rotation on its axis.
a bunch
The orbital is an ellipse. However there is there is very little difference between the major[1AU] and minor[.983AU] axes and for all practical purposes we can take the orbit as a circle
with a radius=1AU=93 million miles.
circumference =2*Pi*r
=2*22/7*93*10^6
=584.57 million miles
which is very close to your answer.
Just multiply 64,000 (mph) X 24 X 365 and you will know.
You are right in what you say, however you are confusing two different things. The earth's speed of spin around its axis is approximately 1,000 mph. TThe Earth rotates once in a few minutes under a day (23 hours 56 minutes 04. 09053 seconds). This is called the sidereal period (which means the period relative to stars). The sidereal period is not exactly equal to a day because by the time the Earth has rotated once, it has also moved a little in its orbit around the Sun, so it has to keep rotating for about another 4 minutes before the Sun seems to be back in the same place in the sky that it was in exactly a day before.
An object on the Earth's equator will travel once around the Earth's circumference (40,075.036 kilometers) each sidereal day. So if you divide that distance by the time taken, you will get the speed of rotation (1670 Kph or 1038 mph).
The earth's speed of orbit around the sun is approximately 67,000 mph. It takes roughly 365 days for the Earth to go around the Sun once. This means that the Earth is rushing through space around the Sun at a rate of about 67,000 miles per hour. The circumference of the Earth's orbit is about 940 million kilometers, so if you divide that by the hours in a year (8760) you will get our orbital speed in kilometers per hour (107306 Kph or 66680 mph)
The path of the earth around the sun is an ellipse. But, it's pretty circular. the earth is actually closest to the sun when the northern hemispere has it's winter. Assuming a circle to make it easy to calculate. you only need to use the formula: 2*pi*r this gives you the circumference. the distance from the sun to the earth is 93,000,000 miles which is r. pi is a constant 3.14. Plug into the eaquation and you get an approx anwers. If you need more accuracy you'll have to use an ellipse which has two foci and some memories that I've lost.
sounds about right. well done.
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