Pand q are points on a circle with center cand the tangents at pandq meet in t. show that pq andt divide?

the diameter along ct harmoniclly

Answers:
consider triangleptc andtriangleqtc. angletpc and angle tqcis 90degrees.cp=cq(radii).ct=ct(c. byr.h.s triangles are congruent that implies pt=qt.
say what?
jimp - first, please, define "pand", "cand", "pandq", "andt", "pq", "ct", and "harmonicily".

Or is it possible that your space bar is sticky?
I must say, you should first learn how to ask questions correctly. PQ does cut the radius in two equal parts, not the diameter.

Let's assume that PQ cuts CT at point R
So, you have to prove now, Triangle PRC and Triangle QRC are equal.

Use some grey cells. I mean it.
what?

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