Dy/dx=cos x, if y(0)=0?



Answers:
dy/dx=cos x

Integrating both sides, we will get:
y = sinx + c

y(0) = sin0 + c = 0 => c=0

So y=sinx.
integrate both sides wrt to x and you get
y= sinx + c c is a constant of integration

substitute y(0) = 0 to find c

0 = sin (0) + c

0 = 0 + c

so c =0

so the answer is y=sinx
dy/dx=cos x, if y(0)=0

dy=coxdx

integrate

y= sinx+ C

y=0 when x=0

so, C+sin0=0
C+0 =0
>>>>>C=0

hence,y=sinx

i hope that this helps
dy/dx = cosx
implies y = -sinx
Therefore y(0) = -sin0
y(0) = 0
Differentiate wrt x
dy/dx = 0

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