In periodic trends and lattice structure, why does O, C, Na,S, fe, & diamond have low or high boiling points.?
why does Oxygen, Carbon, Sodium, Sulphur, Iron, and Diamond have low or high boiling points, and can you explain this in terms of periodic trends and lattice structure.
Answers:
the previous answer is deficient on the following points.
elemental C has the atoms held together by covalent bonding
Na, being a metal, has metallic bonding, not ionic. Ionic bonds occure BETWEEN a metal and a non metal such as Na with Cl.
Metallic character decreases as you cross the periodic table, and increases as you go down the periodic table, so Na is more metallic than Fe
non metallic character does the opposite..
So from the list above, metallic character would be Na > Fe >C > S > O
Na is a metallic lattice while O2 exists as discrete molecules
Hope that helps
Diamond and Carbon are both the same essentially since diamond is a form of carbon. This particular element is a group 4 element. It means it can bond 4 times essentially. When bonding with itself it forms a strong crystal lattice structure. This type of structure has bonds that are really hard to break. With other atoms it tends to go through covalent bonding (read below for that info)
5 types of bonds to consider are Ionic, Covalent,Metallic bonding Hydrogen Bonding, Van der Walls forces, and they go from strong to weak bonds in that order.
Iron has metallic bonding therefore high boilig point. Oxygen exists as O2 and the bonds there are hard to break but between the molecules it is Van der Waals forces it relies on and they are weak, so it has a very low boiling point.
Na can often be seen bonding with non-metals so tends to bond using ionic bonding which requires a high temperature to break the bonds. Sulphur uses convalent bonding like carbon, so has a high boiling point too
And hats off to the answer below. Sorry, I should have specified that you actually tend to find Na in covelant substances.
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Answers:
the previous answer is deficient on the following points.
elemental C has the atoms held together by covalent bonding
Na, being a metal, has metallic bonding, not ionic. Ionic bonds occure BETWEEN a metal and a non metal such as Na with Cl.
Metallic character decreases as you cross the periodic table, and increases as you go down the periodic table, so Na is more metallic than Fe
non metallic character does the opposite..
So from the list above, metallic character would be Na > Fe >C > S > O
Na is a metallic lattice while O2 exists as discrete molecules
Hope that helps
Diamond and Carbon are both the same essentially since diamond is a form of carbon. This particular element is a group 4 element. It means it can bond 4 times essentially. When bonding with itself it forms a strong crystal lattice structure. This type of structure has bonds that are really hard to break. With other atoms it tends to go through covalent bonding (read below for that info)
5 types of bonds to consider are Ionic, Covalent,Metallic bonding Hydrogen Bonding, Van der Walls forces, and they go from strong to weak bonds in that order.
Iron has metallic bonding therefore high boilig point. Oxygen exists as O2 and the bonds there are hard to break but between the molecules it is Van der Waals forces it relies on and they are weak, so it has a very low boiling point.
Na can often be seen bonding with non-metals so tends to bond using ionic bonding which requires a high temperature to break the bonds. Sulphur uses convalent bonding like carbon, so has a high boiling point too
And hats off to the answer below. Sorry, I should have specified that you actually tend to find Na in covelant substances.
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