I am arranging a pool tournament knockout only can someone suggest a format could use?
I HAVE 20 PLAYERS BUT CANT SEEM TO ARRANGE IT
Answers:
PUT 1-20 IN A HAT 1-20, 2-19, 3-18 ECT. IF 1 WIN HE PLAYS THE HIGH WINNING NUMBERS AND SO LONG!!:-)
Easy! Have them all meet at the local bar, and take it from there.
My husband says use a 32-player field (12 buys in the first round, everyone gets assigned a number and gets put in the according slot).
...Yep you have a slight problem here. You either need to get rid of 4 players or get another 12. Even if you get only another 6 players you could still use the format of having 32, just have some of the 1st round matches getting a bye, so you end up with 16 players left to contest round 2, then 8 in the quarter finals 4 in the semi's and 2 for the final. Good luck hope this helps.
put 10 numbers in a pint glass twice .
players who pull the same number play a knock out (best of 3)
10 players left .
put 5 numbers in a pint glass twice .
players who pull the same number play a knock out .
5 players left .
5 players play a round of killer (each person is given 3 lives marked on a chalk board and given one shot each , when they fail to pot they lose a life) , first one out is out of the tournament .
4 players left and back to numbers in a pint glass.
that way their can be no arguments .
Play killer. you start with 3 lives, everyone takes it in turns to have a shot, all you have to do is pot a ball, if you miss or foul you lose a life, the winers the last 1 left.
If you break you get 2 shots
If you pot the black you get an extra life
When there are only 2 balls left on the table (excluding white) you rerack all the balls.
Easy, nobodies stood round for ages, and bad players have a chance as there might be an easy shot on when its there turn.
Put the numbers 1-20 and whoever gets the number 13-20 need to prequalify and the winners of the the four matches to go to the second round. Allow 12 players a bye to the second round, and with the other four winners you have a last 16, last 8, last 4 and final. Hope that helps and good luck.
THE FINAL!!
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Answers:
PUT 1-20 IN A HAT 1-20, 2-19, 3-18 ECT. IF 1 WIN HE PLAYS THE HIGH WINNING NUMBERS AND SO LONG!!:-)
Easy! Have them all meet at the local bar, and take it from there.
My husband says use a 32-player field (12 buys in the first round, everyone gets assigned a number and gets put in the according slot).
...Yep you have a slight problem here. You either need to get rid of 4 players or get another 12. Even if you get only another 6 players you could still use the format of having 32, just have some of the 1st round matches getting a bye, so you end up with 16 players left to contest round 2, then 8 in the quarter finals 4 in the semi's and 2 for the final. Good luck hope this helps.
put 10 numbers in a pint glass twice .
players who pull the same number play a knock out (best of 3)
10 players left .
put 5 numbers in a pint glass twice .
players who pull the same number play a knock out .
5 players left .
5 players play a round of killer (each person is given 3 lives marked on a chalk board and given one shot each , when they fail to pot they lose a life) , first one out is out of the tournament .
4 players left and back to numbers in a pint glass.
that way their can be no arguments .
Play killer. you start with 3 lives, everyone takes it in turns to have a shot, all you have to do is pot a ball, if you miss or foul you lose a life, the winers the last 1 left.
If you break you get 2 shots
If you pot the black you get an extra life
When there are only 2 balls left on the table (excluding white) you rerack all the balls.
Easy, nobodies stood round for ages, and bad players have a chance as there might be an easy shot on when its there turn.
Put the numbers 1-20 and whoever gets the number 13-20 need to prequalify and the winners of the the four matches to go to the second round. Allow 12 players a bye to the second round, and with the other four winners you have a last 16, last 8, last 4 and final. Hope that helps and good luck.
THE FINAL!!
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